Largest possible angle (if no alpha of greater than 30 Mev) is
E tangent (theta sub maximum) = ((beta sub maximum)(((beta exponent 2) - ((beta sub maximum) exponent 2)) exponent (-1/2)))
(theta sub maximum) ~= (0.12/E)
Further, assume the type of collision which produces a bundle of alpha's is equally probably [one's? over?] energy range under consideration.
By this method they obtain for (10 <= Z <= 26) in the energy range (3 <= epsilon <= 20) per / nucleon, the integral numbers spectrum
N(epsilon) = ((K)/((1 + epsilon) exponent (1.25 +- 0.15))
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Again, if alpha's are evaporated with kinetic energy less than 30 Mev or 7.5 Mev / nucleon, their total energy per nucleon in lab system, (E sub 0) will be nearly equal to that of the parent nucleus E.
If [I? J? l?] be the angle in the [rest?] system between direction of motion of the parent nucleus and the emitted alphas, the total energy per nuclear

Largest possible angle (if no alpha of greater than 30 Mev) is
E tangent (theta sub maximum) = ((beta sub maximum)(((beta exponent 2) - ((beta sub maximum) exponent 2)) exponent (-1/2)))
(theta sub maximum) ~= (0.12/E)
Further, assume the type of collision which produces a bundle of alpha's is equally probably [one's? over?] energy range under consideration.
By this method they obtain for (10 <= Z <= 26) in the energy range (3 <= epsilon <= 20) per / nucleon, the integral numbers spectrum
N(epsilon) = ((K)/((1 + epsilon) exponent (1.25 +- 0.15))
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Again, if alpha's are evaporated with kinetic energy less than 30 Mev or 7.5 Mev / nucleon, their total energy per nucleon in lab system, (E sub 0) will be nearly equal to that of the parent nucleus E.
If [I? J? l?] be the angle in the [rest?] system between direction of motion of the parent nucleus and the emitted alphas, the total energy per nuclear