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James Van Allen journal, 1951?-December 1954
Page 58
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substituting the function g(E/(M sub 0)) for v in f(v) ((d(E/(M sub 0)))/(h(E/(M sub 0)))) = ((Z exponent 2)/(M sub 0))([dx? d sub x?) f(E/(M sub 0)) = ( ((integral sub (E/(M sub 0))) exponent ((E/(M sub 0))=0)) ((d(E/(M sub 0)))/(h(E/(M sub 0)))) ) = ((((Z exponent 2)/(M sub 0)))(R)) [red pencil circled below here:] (psi(E/(M sub 0))) = (((Z exponent 2)/(M sub 0))(R)) (<--------2*) or (E/(M sub 0)) = ((psi)(((Z exponent 2)(R))/(M sub 0))) (<--------3*) [red pencil circled above here] ---------------------------------------------------------------------------------------------- For Example: Let (E sub p)=energy of proton of range R (E sub p) = psi (R sub p) (E sub alpha) [or: E(alpha) ?] = energy of alpha particles of same range (((E sub alpha) [or: E(alpha) ?]) / 4) = (psi (R sub alpha)) i.e., alpha particle must have 4 times the energy in order to have the same range.
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substituting the function g(E/(M sub 0)) for v in f(v) ((d(E/(M sub 0)))/(h(E/(M sub 0)))) = ((Z exponent 2)/(M sub 0))([dx? d sub x?) f(E/(M sub 0)) = ( ((integral sub (E/(M sub 0))) exponent ((E/(M sub 0))=0)) ((d(E/(M sub 0)))/(h(E/(M sub 0)))) ) = ((((Z exponent 2)/(M sub 0)))(R)) [red pencil circled below here:] (psi(E/(M sub 0))) = (((Z exponent 2)/(M sub 0))(R)) (<--------2*) or (E/(M sub 0)) = ((psi)(((Z exponent 2)(R))/(M sub 0))) (<--------3*) [red pencil circled above here] ---------------------------------------------------------------------------------------------- For Example: Let (E sub p)=energy of proton of range R (E sub p) = psi (R sub p) (E sub alpha) [or: E(alpha) ?] = energy of alpha particles of same range (((E sub alpha) [or: E(alpha) ?]) / 4) = (psi (R sub alpha)) i.e., alpha particle must have 4 times the energy in order to have the same range.
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