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James Van Allen journal, 1951?-December 1954
Page 66
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altitude = 13.5 g/(cm exponent 2) (P sub emulsion) = 3.91 g/(cm exponent 3) (lambda sub emulstion) = 28. cm (M.F.P. using [(sigma sub geometrical)? (sigma geometrical)?]) ------------------------------------------------------------- Neglect absorption in stack of plates (may not be too small ~5 cm of path?) ----------------------------------------------------------------- Gross Correction: (lambda sub air) = 65 (h/lambda)=13.5/65=0.208 ((I(h))/(I(O)))=( (e exponent (-(h/lambda))) + (h/lambda)(Ei(-h/lambda)) ) =0.813 + (0.208)(-1.1905) = 0.813 - 0.248 (I(13.5)) / (I(O)) = 0.565 correct to top of atmosphere 32/0.565 = 57/(gm - day) = (57)(3.91) = 222/((cm exponent 3) day) (2.56 x (10 exponent -3))/((cm exponent 3)(second))
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altitude = 13.5 g/(cm exponent 2) (P sub emulsion) = 3.91 g/(cm exponent 3) (lambda sub emulstion) = 28. cm (M.F.P. using [(sigma sub geometrical)? (sigma geometrical)?]) ------------------------------------------------------------- Neglect absorption in stack of plates (may not be too small ~5 cm of path?) ----------------------------------------------------------------- Gross Correction: (lambda sub air) = 65 (h/lambda)=13.5/65=0.208 ((I(h))/(I(O)))=( (e exponent (-(h/lambda))) + (h/lambda)(Ei(-h/lambda)) ) =0.813 + (0.208)(-1.1905) = 0.813 - 0.248 (I(13.5)) / (I(O)) = 0.565 correct to top of atmosphere 32/0.565 = 57/(gm - day) = (57)(3.91) = 222/((cm exponent 3) day) (2.56 x (10 exponent -3))/((cm exponent 3)(second))
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